How does mass vary during the dissolution of sugar in water? 🧂💧

The solvent is the liquid that dissolves the liquid, solid, or gas. It is the majority substance.

The solute is the solid, liquid, or gas that is dissolved by the solvent. It is the minority product.

The solution is the liquid obtained by dissolving the solute in the solvent. It is a homogeneous mixture.

Example:
Case of chocolate milk
- The solute is the chocolate.
- The solvent is the milk.
- The solution is the chocolate milk.

The balance indicates 0.0 g.

m_Beaker = 27 g
m_Water = 100 g
m_{3 sugars} = 18 g

m_Beaker = 27 g
m_{Sugared water} = 118 g

• Step 1: Turn on the balance and wait for it to indicate 0.0 g.
  
  
• Step 2: Place a 27 g beaker containing 100 mL of water and 3 sugars of 6 g on the balance. The balance displays 145 g. Note this value as m₁.
  
  
• Step 3: Put the 3 sugars into the beaker and stir slowly until the sugar is completely dissolved. Then place the beaker back on the balance. The balance displays 145 g. Note this value as m₂.
  
  
• Step 4: Compare m₁ and m₂.
  If m₁ = m₂, the mass is conserved during this dissolution.
  
  

Initially:
m_I = m_Water + m_Sugar
m_I = 18 g + 100 g = 118 g

Finally:
m_F = m_{Sugared water}
m_F = 118 g

Conclusion:
m_I = m_F = 118 g

The mass does not vary during the dissolution of sugar in water. 🧪
Mass is conserved during dissolution.

m_Solution = m_Solute + m_Solvent

The mass of the solution is equal to the sum of the mass of the solute and the mass of the solvent.