MCQ: Choose the correct answer(s)

1. A solution that can no longer dissolve sugar is:
• a saturated salt solution a sugary solution a saturated sugar solution

2. When salt is added to a saturated salt solution, we obtain:
• A B C

3. The formula to calculate solubility s is:
•   \( s = {\displaystyle\frac{m_{\text{max solute}}}{V_{\text{solution}}}} \)    \( s = {\displaystyle\frac{V_{\text{solution}}}{m_{\text{max solute}}}} \)     \( s = V_{\text{solution}} \, / m_{\text{max solute}} \)     \( s = m_{\text{max solute}} \, : V_{\text{solution}} \)  

4. The solubility of sugar in water is 2000 g/L, so one liter of saturated sugary water contains:
• 2 kg of sugar 1 L of sugar 2000 g of sugar

5. In \( 200 \, \text{mL} \) (\( 0.2 \, \text{L} \)) of water, we can dissolve \( 20 \, \text{g} \) of sodium bicarbonate. Therefore, the solubility s of sodium bicarbonate in water is equal to:
• \( s = \displaystyle\frac{20} {200} = 0.1 \, \text{g/L} \) \( s = \displaystyle\frac{0.2} {20} = 0.01 \, \text{g/L} \) \( s = \displaystyle\frac{20} {0.2} = 100 \, \text{g/L} \)

6. In \( 50 \, \text{mL} \) (\( 0.05 \, \text{L} \)) of water, only \( 18 \, \text{g} \) of coffee can be dissolved. Therefore, the solubility s of coffee in water is equal to:
• \( s = \displaystyle\frac{18} {50} = 0.36 \, \text{g/L} \) \( s = \displaystyle\frac{18} {0.05} = 360 \, \text{g/L} \) \( s = \displaystyle\frac{0.05} {18} = 0.003 \, \text{g/L} \) \( s = \displaystyle\frac{18} {0.05} = 360 \, \text{L/g} \)

RESULT: